Hi, Phil,

Perhaps I am not figuring out the efficiency correctly,
but I only get about 36% efficiency. It doesn't seem to be
the throw because Chris says that he used a throw of +/-2'
and got the same temperature of about 7K toward Venus as
I did with a throw of +/-3'. 

I used the formula:

eta_fss * [T_a*(planet)/T_bb(planet)][1-exp(-(D^2/theta^2)ln 2)]^(-1)

Where T_a*(planet) = 7K/eta_fss
      T_bb(planet) = 367 at 90GHz (I'm at 114.7GHz, but at
				   227GHz it is 317K.)
      D = 12.94"
      theta = 53.6"
      ets_fss = .75

Is this correct or is there something I can do to make this 
a higher efficiency?

Connie


*************************************
Worried we were on the wrong Vlsr. Text had said HI absorption
line at 1420km/s. Looked like a map said 1520km/s:

I think that map is an emission line map in HI;
so I think we're ok. 
Sorry; I am just trying to keep a check on things.

Nothing yet.

Oh, we have to stop observing for about an hour to
an hour and a half because this source will go right
through zenith and looses its pointing capabilities.

I also had to repoint on the 4c39.25 quasar when we
changed to +/-1.5' throw, because the pointing sometimes
changes for different throws. Unfortunately it means having
to take the telescope all the way around the other way.

I also did two quick scans on Venus for an efficiency
test and came up with only 36% for main beam efficiency!
YUCK. That was for a +/-3' throw. In the dead time, I
will try doing a couple of scans on Venus again.

Connie
*****************************************


15 minutes to go. I think that there may be some
at about 1450km/s +/- 40km/s or so. But the "absorption
line" is less than .01K. The continuum is a little more
than .02K.

C
****************************************

In the FB, I think we see emission above the continuum
on the order of 8mK from 1484 to 1547 km/s.